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two negative integers are 8 units apart on the number line and have a product of 308. which equation could be used to determine extra small or negative integer?

User Fduayer
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2 Answers

6 votes
Let's give it a try. Let the integers be x and y, understanding that both are -.

x - y = 8

x(y) = 308 Solve the first equation for x: x = 8+y. Subst. this result into the second equation:

(8+y)(y) = 308, or y^2 + 8y - 308 = 0

Quadratic equation with a=1, b=8 and c= -308.
-8 plus or minus sqrt(64-4(1)(-308) )
Then y = ----------------------------------------------------
2

Can you finish the arithmetic here? Find the 2 values of y.
User Vittorio
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3 votes

Answer:

x^2 + 8x - 308 =0

Explanation:

User Dmitriy  Korobkov
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