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What's the value of 3y2 + 2z when y = 4 z= -7

1 Answer

3 votes
y= 4
z= -7

Substitute the given values above in for each variable in the expression below.


= 3y^2 + 2z

= 3(4)^2 + 2(-7)
using order of operations, square 4 before multiplying (PEMDAS: parentheses, exponents, multiplication, division, addition, subtraction)

= 3(16) + (-14)
a positive times negative is negative

= 48 - 14

= 34


ANSWER: 34

Hope this helps! :)
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