Register
The diagonals of rectangle nopq intersect at point r. if qr=3x-4 and np=5x+20, solve for x.
181k views
0 votes
The diagonals of rectangle nopq intersect at point r. if qr=3x-4 and np=5x+20, solve for x.

User JVXR
by
6.1k points

1 Answer

5 votes
The diagonals of a rectangle are congruent. We have half of diagonal QO and the whole diagonal of NP. So the equation will look like this: 5x+20=2(3x-4). 5x+20=2(3x-4). 5x + 20 = 6x - 8. 28 = x. Therefore, x = 28 and the length of the diagonals is 160
User Deming
by
6.2k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.7m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
Link Copied!