Question

Which is one of the transformations applied to the graph of f(x)= x2 to produce the graph of p(x)= -50+14x-x2

Answer 1

Let's find the coordinates of parabola vertex:

`x_v= (-b)/(2a) =- (14)/(2\cdot(-1)) =7 \\ y_v=-50+14\cdot 7-7^2=-50+98-49=-1`, so the vertex is placed at point (7,-1).
Since in the equation
`p(x)=-50+14x-x^2` the member
`x^(2)` is with minus sign, then you should do such transformation with graph of function
`f(x)= x^(2)`:
1. Reflect graph about the x-axis;
2. Translate reflected graph 7 units right and 1 unit down.