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3 votes
What is the cube root of -1000p^12q^3

2 Answers

5 votes
∛(-1000p^12q^3)
= -10p^4 q

Hope it helps
User Bsmarcosj
by
8.0k points
6 votes

Answer:


-10p^4q

Explanation:

Using the exponent rules:


\sqrt[n]{a^n} = a


\sqrt[3]{-1} = -1

To find the cube root of :


-1000p^(12)q^3

then;


\sqrt[3]{-1000p^(12)q^3}

We can write :


1000 = 10 \cdot 10 \cdot 10 = 10^3


p^(12) = (p^4)^3

then;


\sqrt[3]{-10^3 \cdot (p^4)^3 \cdot q^3}

Apply the exponent rules:


-10 \cdot p^4 \cdot q


-10p^4q

Therefore, the cube root of
-1000p^(12)q^3 is,
-10p^4q

User Sergio Prado
by
8.0k points

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