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What is the value of the rational expression 2x2+5x+9/x2+2x-1 when x=-2

User Ehime
by
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2 Answers

1 vote
The answer is -7.

In order to find this, try evaluating the numerator and denominator separately and then divide afterwards.

Numerator:
2x^2 + 5x + 9
2(-2)^2 + 5(-2) + 9
2(4) - 10 + 9
8 - 1
7

Denominator:
x^2 + 2x - 1
(-2)^2 + 2(-2) - 1
4 - 4 - 1
-1

Now divide the answers
7/-1 = -7
User Spackmat
by
5.1k points
1 vote

Answer:

The value of given expression at x=-2 is -7.

Explanation:

The given expression is


(2x^2+5x+9)/(x^2+2x-1)

Substitute x=-2 in the above expression.


(2(-2)^2+5(-2)+9)/((-2)^2+2(-2)-1)

Solve the squares and brackets.


(2(4)-10+9)/(4-4-1)


(8-1)/(-1)


(7)/(-1)


-7

Therefore the value of given expression at x=-2 is -7.

User Wgp
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5.3k points