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Given: F(x) = 3x 2 + 1, G(x) = 2x - 1, H(x) = x FG = 4x² 12x²+4 12x²-12x+4
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3 votes
Given: F(x) = 3x 2 + 1, G(x) = 2x - 1, H(x) = x

FG =


4x²

12x²+4

12x²-12x+4

User Mike Rifgin
by
7.8k points

1 Answer

0 votes


f(x) = {3x}^(2) + 1 \\ g(x) = 2x - 1
FG(x) = you insert g(x) into f(x)
So,

3(2x - 1) {}^(2) + 1 \\ = 3(4x {}^(2) - 4x + 1) + 1 \\ = 12x {}^(2) - 12x + 3 + 1 \\ = 12 {x}^(2) - 12x + 4
So the answer is the bottom one
User Kay Zed
by
8.0k points
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