Quin's velocity is given by the resultant of the two velocities. If we assume east as positive direction, the two velocitiies are:
![v_q =+1.6 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/fbwlbs46gm2z532qiwdxrcuv24zn2l2xbl.png)
is Quin's velocity in his reference frame
![v_b=-0.3 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/yclmrgg4j2fwzrjxkkdvfoe1fia3acca7a.png)
is the belt velocity (with a negative sign since it is due west)
Therefore, the resultant is
![v_T=v_q+v_b=+1.6 m/s-0.3 m/s=+1.3 m/s](https://img.qammunity.org/2019/formulas/physics/high-school/7et2ht2b3hq47c73j3dtxhsicarkfhk9rl.png)
and the sign tells us the velocity is due east.