Question

How many total atoms are in 0.610 g of P2O5?

Answer 1

The total number of atoms in 0.610 g of P2O5 is approximately 2.589 × 10^21 atoms, calculated by finding the number of moles from the given mass and then multiplying by Avogadro's number.

Step-by-step explanation:

To calculate the total number of atoms in 0.610 g of P2O5, we need to determine the number of moles present in this mass and then use Avogadro's number to convert from moles to atoms. The molar mass of P2O5 (molecular mass of diphosphorus pentoxide) is the sum of the atomic masses of 2 phosphorus (P) atoms and 5 oxygen (O) atoms, which is (2 × 30.973761 amu) + (5 × 15.9994 amu) = 141.944522 amu per mole. Using this molar mass:

Number of moles of P2O5 = Mass (g) ÷ Molar Mass (g/mol)
= 0.610 g ÷ 141.944522 g/mol
= 0.00430 mol

Now, using Avogadro's number (6.022 × 1023 atoms/mol), we can find the total number of atoms:

Total atoms in 0.610 g of P2O5 = Moles × Avogadro's number
= 0.00430 mol × 6.022 × 1023 atoms/mol
= 2.589 × 1021 atoms

Therefore, there are approximately 2.589 × 1021 atoms in 0.610 g of P2O5.

Answer 2

To find the answer one must first find the mole ratio in P2O5.
0.610grams roughly equals to 0.004 mol of P2O5
1 mole is equal to 6.02 x 10^23
(6.02x10^23) x 0.004 = 2.408x10^21
There are 2.408x10^21 atoms in 0.61g of P2O5