Question

Q,# 12 please help to resolve

Answer 1

Hi there!

Accr'ding to given conditions in th' question :-

I. The box is x feet wide.
II. The box is twice long as it's wide.
III. The height of the box is 3 feet less than width.

• Width, w = x
• Length, l = 2x
• Height, h = (x - 3)

It's known :-

Volume of box = w × l × h

Volume of box = x × (2x) × (x - 3)

Volume of box = 2x² × (x - 3)

Volume of box = 2x³ - 6x²

Hence,
Option [ 2. ] : 2x³ - 6x² is Correct.

~ Hope it helps!

Answer 2

The right answer is B

We know the following statements regarding the box:

1. The box is rectangular
2. It's twice as long as it is wide
3. The height of the box is 3 feet less than the width
4. x: feet wide

So we can apply a mathematical language to solve this problem.

The volume of a rectangular box can be find by:


`V=W* L* H \\ \\ where \\ \\ W:Width \\ L:Length \\ H:Height`

But we also know that:


`W=x`

The other statement states that the box is twice as long as it is wide, that is:


`L=2x`

A statement says that the height of the box is 3 feet less than the width, so this is given by:


`H=x-3`

So combining these results:


`V=x(2x)(x-3) \\ \therefore V=2x^2(x-3) \\ \therefore \boxed{V=2x^3-6x^2}`