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3. Chords AB and CD intersect inside a circle at point E. AE= 5, CE =10, EB = x, and ED = x-4. Find EB and ED.
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3. Chords AB and CD intersect inside a circle at point E. AE= 5, CE =10, EB = x, and ED = x-4. Find EB and ED.

User Adam Hunyadi
by
5.4k points

1 Answer

3 votes
we know that
When two chords intersect each other inside a circle, the products of their segments are equal (Intersecting Chord Theorem)
so
AE*EB=CE*ED
5*x=10*(x-4)
5x=10x-40
10x-5x=40
5x=40
x=40/5
x=8

therefore
EB=x----------> EB=8
ED=x-4---------> ED=8-4-----> ED=4
User Sourcerer
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