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Find the center of the circle whose equation is 3x² + 3y² = 75.

User Sole Galli
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2 Answers

5 votes
3x^2 + 3y^2 = 75

Dividing through by 3 we get

x^2 + y^2 = 25

The center is at (0,0) answer
User Mooh
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7.2k points
2 votes

Answer:

Center = (0,0)

Explanation:

The standard form of a circle is


(x-h)^2+(y-k)^2=r^2 ..... (1)

where, (h,k) is the center of the circle and r is radius.

The given equation is


3x^2+3y^2=75

Divide both sides by 3.


x^2+y^2=25


x^2+y^2=5^2 ..... (2)

On comparing (1) and (2) we get

h=0, k=0, r=5

Therefore, the center of the circle is (0,0) and radius of the circle is 5.

User Gareve
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6.3k points