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What are the domain and range of f(x)= (1/6)^x +2

User Nizzik
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2 Answers

2 votes

Answer:

(っ◔◡◔)っ ♥ C ♥

Explanation:

got it right on edge :)

3 votes
For basic exponential functions the domain is "all real numbers." The graph is above the x-axis and never touches it, so the range is (0, infinity).

For f(x) = (1/6)^x + 2, the domain is the same as before, but the range changes. There will be no graph touching the line y = 2 or showing up below that line. Range is (2, infinity).

User Sirish V
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