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Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
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3 votes
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

User Zvikara
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1 Answer

4 votes
(-3,11) & (1,-3)
x1 y1 x2 y2


-3-11 -14 -7
1+3 4 2


y=-7/2x+b
11=-7/2(-3) +b
11=21/2+b
22/2=21/2+b (subtract 21/2 from each side)
1/2=b

so it would be y=-7/2x + 1/2
User Aforankur
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