Question

Please answer the question!!?

Answer 1

g(x) = (x-3)^2 - 1 or D

Answer 2

d).
`g(x)= (x -3)^(2) -1`

Explanation:

The original function
`f(x) = x^(2)` began from the origin mean that when x=0 the is going to be y=0

Using the standard equation quadratic function:

`y= a*(x-h)^(2) +k\\h= 3` ,
`k=-1`,
`a=1`

Solving:

`y=1*(x-3)^(2) + (-1)\\y=(x-3)^(2) -1`

The second function have origin in the point (3,1) so making the function x=3

`g(x)= (x -3)^(2)-1\\g(3)= (3 -3)^(2)-1\\ g(3)=-1`