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41 votes
41 votes
Jane is 3 years older than Mary. Mary is twice as old as Kay. If Kay is x years how old is jane

User Frederick Marcoux
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2 Answers

14 votes
14 votes

Jane is 2x+3 years old. (answer)

In this case, we can use Kay as the base/foundation in this problem. Kay is x years old. Mary is twice as old as Kay, making Mary 2 times x or 2x. We are solving for Jane. Jane is 3 years older than Mary, who we know is 2x. We can add on 3 years making the final expression for Jane's age: 2x+3. Since we do not know Kay's age, or x, we cannot solve this problem any further.

User Yann Thibodeau
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3.0k points
5 votes
5 votes
Kay = x

Mary = 2x

Jane = 2x+3
User Vasil Dakov
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3.4k points