232k views
2 votes
What is the sum of the first five terms in a geometric sequence with a1 = 6 and r=1/3

2 Answers

4 votes

Answer: 121/27

Explanation:

Precalc

User Jacob H
by
5.0k points
5 votes
To solve this problem you must apply the proccedure shown below:
1. You have that a1=6 and r=1/3, therefore you must apply the following formula:
Sn=a(1-r^n)/1-r
2. When you substitute the values shown above, you obtain:
S5=6(1-(1/3)^5)/(1-(1/3))
S5=242/27
Therefore, the answer is 242/27
User Adindu Stevens
by
5.4k points