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P(x)=21+24x+6x^2 in vertex form

User Neallred
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1 Answer

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We want vertex form: y-k=(x-h)^2.

Re-write P(x)=21+24x+6x^2 as P(x)=6x^2 + 24x + 21

Factor the first 2 terms as shown: P(x)=6(x^2+4x )+ 21

complete the square of (x^2+4x): P(x) =6(x^2 + 4x + 4 - 4) + 21

Rewrite the quadratic: P(x) = 6(x+2)^2 - 24 + 21

Simplify this result: P(x) = 6(x+2)^2 - 3
Compare this to y-k = a(x-h)^2

Identify k as -3 and h as -2; vertex is at (-2,-3)

P(x) in vertex form is P(x) = 6(x+2)^2 - 3
User Dennis Lu
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