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The product of ab=1200. a is an integer and b is an odd integer. What is the largest possible value of b

2 Answers

4 votes

Answer:

75

Explanation:

Factoring out the highest power of 2 from 1200, we find that
$1200=2^4\cdot75$. Therefore, the largest possible value of
$b$ is
$\boxed{75}$.

Hope this helped! :)

User Matwilso
by
8.7k points
4 votes

Answer:

Largest possible value of b is:

75

Explanation:

we are given that:

ab=1200

where a is an integer and b is an odd integer.

we know that product of odd numbers is always odd.

Now, 1200= 12×100

= 2×6×10×10

=2×2×3×2×5×2×5

It cannot be factorized further

Now, considering the product of all odd numbers

=3×5×5

=75

Now, if we multiply any other remaining number from the factorization of 1200, we will get a even number

Hence, The largest possible value of b is:

75

User Muhammad Gelbana
by
8.1k points

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