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Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

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Answer:

The answer is (a, a)

User Colin Grogan
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The formula of the midpoint of HE:

\left((x_H+x_E)/(2);\ (y_H+y_E)/(2)\right)

We have H(0; 0) and E(2a; 2a). Substitute:

\left((0+2a)/(2);\ (0+2a)/(2)\right)=(a;\ a)

User Chriki
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