Question

Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he

Answer 1

The answer is (a, a)

Answer 2

The formula of the midpoint of HE:

`\left((x_H+x_E)/(2);\ (y_H+y_E)/(2)\right)`

We have H(0; 0) and E(2a; 2a). Substitute:

`\left((0+2a)/(2);\ (0+2a)/(2)\right)=(a;\ a)`