Question

What is slope of a line that passes (-12,15)and(0,4)?

Answer 1

Hi there!

• ( x₁ , y₁ ) = ( -12 , 15 )
• ( x₂ , y₂ ) = ( 0 , 4 )

by Slope formula :-

m =
`\frac {y_(2) - y_(1) }{x_(2) - x_(1) }`

=> m =
`\frac {4 - 15}{0 - (-12)}`

=> m =
`\frac {-11}{0 + 12}`

=> m =
`\frac {-11}{12}`

Hence,
The slope of th' line is
`\frac {-11}{12}`

~ Hope it helps!

Answer 2

Given points:
(x₁,y₁) = (-12,15)
(x₂,y₂) = (0,4)

Use slope formula

`m= (y_(2)-y_(1))/(x_(2)-x_(1))`

`m= (4-15)/(0-(-12))`

`m= (-11)/(0+12)`

`m= -(11)/(12)`

The slope of the line is equal to -11/12