Question

A student using this technique finds that when putting a hot piece of metal into a calorimeter which contains 35.070g of water, the water temperature increases from 22.4 c to 24.7

c. how much heat (q) was absorbed by the water (s.h of water = 4.184 j/g k)

Answer 1

Q=cmΔt,

c=4.184 j/(g*⁰C)
m=35.070 g
Δt=t(final)-t(initial) = 24.7-22.4=2.3⁰C

Q=4.184 j/(g*⁰C)* 35.070 g * 2.3⁰C ≈ 337.49 J ≈ 338 J