Answer:
![m\angle A = 10^\circ](https://img.qammunity.org/2019/formulas/mathematics/college/81vpqwqpy2ygkat9afinmdrvjwhpr996tk.png)
Explanation:
We are given the following information in the question:
![ABCD \cong QRST\\m\angle A = x -10\\m\angle Q = 2x-30](https://img.qammunity.org/2019/formulas/mathematics/college/h8d8wbqwywwr15zqir9ej0zqdh22rqm5s5.png)
Since,quadrilateral ABCD is congruent to the quadrilateral QRST, then by the property of congruency, we can write,
![m\angle A = m\angle Q](https://img.qammunity.org/2019/formulas/mathematics/college/gnk56shcl89f1jem71swpx45c7uqx2sfbm.png)
Equating the value of the two angles, we get,
![m\angle A = m\angle Q\\x - 10 = 2x - 30\\2x - x = 30-10\\x = 20](https://img.qammunity.org/2019/formulas/mathematics/college/9ah2o9d9zgim8lkdvroyl8xsnxay5camrx.png)
Putting the value of x to obtain measure of angle A.
![m\angle A = x -10 = 20-10\\m\angle A = 10^\circ](https://img.qammunity.org/2019/formulas/mathematics/college/rusqi1n3z1o8htmmk7y1lm0oku59p9c6w7.png)
Thus, the measure of angle A is 10 degrees.