Question

(3x+4)^2=14 what are the solutions?

Answer 1

`\bf (3x+4)^2=14\implies √((3x+4)^2)=\pm√(14)\implies 3x+4=\pm√(14) \\\\\\ 3x=\pm √(14)-4\implies x=\cfrac{\pm √(14)-4}{3}\implies x= \begin{cases} \cfrac{√(14)-4}{3}\\\\ \cfrac{- √(14)-4}{3} \end{cases}`