Question

A line contains the points (1, –6) and (–2, 6). What is the slope of a line that is perpendicular to this line?

Answer 1

First, find the slope of the line contains the points (1,-6) and (-2,6) using slope formula
m =
`(y_(2)-y_(1))/(x_(2)-x_(1))`

plug in the numbers
m =
`(6-(-6))/(-2-1)`
m =
`(6+6)/(-3)`
m =
`(12)/(-3)`
m = -4

Second, determine the slope of perpendicular line
The slope of the perpendicular line is the opposite and reciprocal from the other line. Thus, the slope is
`(1)/(4)`