Question

What are the zeros of the polynomial function y=2x^3-7x^2+2x+3?

Answer 1

`y = 2 {x}^(3) - 7 {x}^(2) + 2x + 3`

By inspection 1 is a root of y ,
Hence , (x-1) is a factor of y ,


`\frac{2 {x}^(3) - 7 {x}^(2) + 2x + 3 }{x - 1} = 2 {x}^(2) - 5x - 3 \\ \\ 2 {x}^(2) - 5x - 3 = (2x + 1)(x - 3)`

Hence , the 2 other roots are -1/2 and 3 , and the above graphs confirms the same.

Hope it helps you :)