Answer:
1.19
Explanation:
We are given that a function
f(x)=
cube root of 108
We have to find the simplified base of the given function
![f(x)=(1)/(4)\[tex]\sqrt[3]{108}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/sa449jarg4olxsg9esrcs196jd3i58omf4.png)
![f(x)=(1)/(4)\sqrt[3]{3*3*3*2*2}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/1tk6umd4khgxqbs3wfw2kmehiqeit0u23m.png)
![f(x)=(1)/(4)* 3\sqrt[3]{4}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2qntvegf731e16v6re6k4g2a6e2dzfasmm.png)
When we finding cube root by the prime factorization formula then we fins prime factors of given number and then we make pair of three same factor then that single number comes out of cube root.


The base of simplified base of function is 1.19.
Answer :1.19