You will FOIL this out to simplify. First outers, inners last. 2*1 = 2; 2*2sqrt7 = 4sqrt7; -sqrt7*1=-sqrt7; -sqrt7*2sqrt7 = 2sqrt49. This is what all that looks like:
![2+4 √(7)- √(7)-2 √(49)]()
. Combining like terms we have
![2+3 √(7) -2 √(49)]()
. The sqrt 49 is equal to 7, so we can continue simplifying:
![2+3 √(7)-2(7)]()
which equals
![2+3 √(7)-14]()
. Finally,
![-12+3 √(7)]()
. Or, putting the positive term first, it would also be correct to write
![3 √(7)-12]()