Question

A bag contains 3 red

marbles, 5 blue marbles and 4 green marbles. If three marbles
are drawn out of the bag, what is the exact probability that all three marbles drawn
will be blue?

Can y’all help me please??

Answer 1

`(5)/(42)`

Explanation:

It makes a difference if the marbles are place bag into the bag after selecting. Since this is not stated, I am assuming that once a marble is selected, it is not placed back in the bag.

`(5)/(9)` x
`(4)/(8)` x
`(3)/(7)` =
`(60)/(504)` This simplified would be
`(5)/(42)` The 5 represent the number of blue marbles available our of 9 total marbles. Next, we only have 4 blue marbles available out of a total of now 8 marbles and lastly, for the third draw we only have 3 blue marbles available and only 7 total marbles are left.

If the marbles are replaces that changes the problem and the answer would be
`(5)/(9)` x
`(5)/(9)` x
`(5)/(9)` =
`(121)/(729)`