Answer: 1-A.) 0.14
2-C.) 0.3
Step-by-step explanation:
1.) The number of persons who have iron deficiency and is less than 20 years old =41
The total number of persons surveyed = 3000
Thus, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old

Hence, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old = 0.14
2.) The number of persons who do not have iron deficiency and is more than 20 years old =43+46=89
Thus, the probability of randomly choosing a person who do not have iron deficiency and is more than 20 years old

Hence, the probability of randomly choosing a person who do not have iron deficiency and is more than 20 years old =0.3