Answer:
The cost of the tiles to re-tile the bottom of the pool is $3000
Explanation:
* Lets use the attached figure to solve the problem
- The pool is symmetrical and shaped like the letter “W” as the
attached figure
- Each tile covers 1/2 of a square yard and costs $3
- To find the area of the pool we consider the pool consists of two
rectangles with dimensions 20 yards and 10 yards and a square of
side 10 yards
∵ The area of the rectangle is the product of the two dimensions
∵ The area of the square is side × side
∴ The area of the pool = 20 × 10 + 20 × 10 + 10 × 10
∴ The area of the pool = 200 + 200 + 100 = 500 yard²
- Each tile covers 1/2 yard²
∴ The number of tiles = area pool ÷ area tile
∴ The number of tiles = 500 ÷ 1/2 = 1000 tiles
- The cost of each tile is $3
∵ The cost of the tiles = number of tiles × cost of 1 tile
∴ The cost of the tiles = 1000 × 3 = 3000
* The cost of the tiles to re-tile the bottom of the pool is $3000