The correct answer is:
You can map ABC to A'B'C' by translating it 6 units left and reflecting it across the x-axis, which is a series of rigid motions.
Explanation:
In ABC, the coordinates are:
A(1, -3)
B(5, 3)
C(4, -1).
In A'B'C', the coordinates are:
A'(-5, 3)
B'(-1, -3)
C'(-2, 1)
Each point is mapped to its image:
A(1, -3)→A'(-5, 3)
B(5, 3)→B'(-1, -3)
C(4, -1)→C'(-2, 1)
Comparing the x-coordinates in the pre-image and image, we notice that the image has an x-coordinate that is 6 less than that of the pre-image:
1-6 = -5
5-6 = -1
4-6 = -2
This means that the figure must be translated 6 units left; that is the only way to have this change on the pre-image to form the image.
Comparing the y-coordinates of the pre-image with those of the image, we notice that they are negated:
-(-3) = 3
-(3) = -3
-(-1) = 1
This means the pre-image was reflected across the x-axis; this is the only way to negate the y-coordinate and not change the x-coordinate.
These are rigid motions because they do not change the shape or size, they simply move it and change its orientation.