Question

A student balances the following redox reaction using half-reactions. AL+Mn2+->AI3+Mn2 How many electrons will be lost in all? 1 2 5 6

Answer 1

Answer:6

Step-by-step explanation:

Answer 2

The number of electron lost are 2

Explanation
Al +Mn^2+→ Al^3+ + Mn2

from equation above the oxidation of Al move from zero( 0) to positive three (3^+), while the oxidation of Mn move from oxidation state positive two( 2^+) to Zero. Since the oxidation for Mn is reduced from 2^+ to 0 the number of electron lost are 2