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Solve. 10e^-0.1234x =20

User Mana
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1 Answer

5 votes
Divide by 10 and take the natural log.
e^(-0.1234x) = 2
-0.1234x = ln(2)
x = -ln(2)/0.1234
x ≈ -5.617076
User Jregnauld
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