Question

Question Progress

Homework Progress
24 / 63 Marks
a) Work out the value of (15)*× (√3)?
x
b) Work out the value of (19) × (√30) ?
x
1 14
豐
54%

Answer 1

Now we have to,

→ work out the value for the following.

We know that,

→ square ( ²) and square root (√) gets cancelled each other.

→ cube ( ³) and cube root (³√) gets cancelled each other.

a) (√5)² × (√3)² = ?

→ (√5)² × (√3)²

→ 5 × 3 = 15

Thus, the answer is 15.

b) (³√9)³ × (√30)² = ?

→ (³√9)³ × (√30)²

→ 9 × 30 = 270

Thus, the answer is 270.

Answer 2

(a) 15

(b) 270

Explanation:

Part (a)

Given expression:

`\left(√(5)\right)^2 * \left(√(3)\right)^2`

`\textsf{Apply the exponent rule}:\quad \left(\sqrt[n]{a}\right)^n=a,\quad \textsf{$n$ is odd or $a \geq 0$}`

`\implies 5 * 3`

Multiply the numbers:

`\implies 15`

Part (b)

Given expression:

`\left(\sqrt[3]{9} \right)^3 * \left(√(30)\right)^2`

`\textsf{Apply the exponent rule}:\quad \left(\sqrt[n]{a}\right)^n=a,\quad \textsf{$n$ is odd or $a \geq 0$}`

`\implies 9 * 30`

Multiply the numbers:

`\implies 270`