Hi there!
| 5x +
![2](https://img.qammunity.org/2019/formulas/mathematics/college/1tpoxbp8mbu4h20xmb8ybcxwgwmu840mr5.png)
| = 8
• Absolute Value :-
The Absolute Value or Modulus | X | of a real number x is the non-negative value of x without regard to its sign.
Which makes the above Eqn's right hand side + ve in both cases.
Then,
Isolatin' the Absolute Value :-
→ For + ve value :
=> 5x + 2 = 8
=> 5x = 8 - 2
=> 5x = 6
=> x =
![\frac {6}{5}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zvl5edbaz9skfr6ob95jeqyr1soqojdc89.png)
→ For - ve value :
=> 5x + 2 = -8
=> 5x = - 8 - 2
=> 5x = - 10
=> x =
![\frac {- 10}{5}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/o364lr1vwgxkepi4iq59ldulo4qs1yd1mj.png)
= -2
Hence,
Solution for the Eqn. are :-
=> x = -2 Or => x =
![\frac {6}{5}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zvl5edbaz9skfr6ob95jeqyr1soqojdc89.png)
~ Hope it helps!