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What is the equation in standard form of the line that contains points c(-2,-4) and d(2,2)

User MontDeska
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The slope of this line is
2-(-4) 6
m = ------------ = ------- = 3/2
2-(-2) 4

Starting with y = mx + b, we get 2 = (3/2)(2) + b, or b = -1

Then the equation is y = (3/2)x - 1. Now let's change this into standard form:

Mult all terms by 2: 2y = 3x - 2. Move 2y to the right side: 3x - 2y - 2 = 0. This is in standard form.

User Mikayla
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