Question

Find the solution set. x^2+5x-6=0

Answer 1

-6 and 1 would be the solution set

Answer 2

`\displaystyle x^2+5x-6=0 \\ \\ \Delta=b^2-4ac\\ \Delta=5^2-4\cdot1\cdot(-6) \\ \Delta=25+24=49 \\ \\ X_(1,2)= (-b \pm √(\Delta) )/(2a) \\ \\ X_1= (-5-7)/(2) = -(12)/(2) =-6 \\ \\ X_2= (-5+7)/(2)= (2)/(2) =1 \\ \\ \text{The solution set: -6 and 1}`