Question

Find the coordinates of the midpoint of a segment with the endpoints (16,5) & (28,-13)

Answer 1

`\text{The formula of the midpoint of a segment with the end points:}\\\\A(x_A;\ y_A)\ \text{and}\ B(x_B;\ y_B)\\\\M_(AB)=\left((x_A+x_B)/(2);\ (y_A+y_B)/(2)\right)`


`\text{We have:}\\A(16;\ 5)\to x_A=16;\ y_A=5\\B(28;\ -13)\to x_B=28;\ y_B=-13\\\\\text{substitute:}\\\\M_(AB)=\left((16+28)/(2);\ (5+(-13))/(2)\right)=\left((44)/(2);\ (-8)/(2)\right)=(22;\ -4)`