Question

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parentheses 6 minus 6 i close parenthe . (6 points)

1. quantity of negative 3 minus 6 i over 5
2. quantity of 39 minus 6 i over negative 9
3. quantity of negative 39 minus 6 i over 17
4. quantity of 3 minus 6 i over 3

Answer 1

A calculator shows

`(√(-9))/((4-7i)-(6-6i))=(3i)/(-2-i)=-3\cdot(i(2-i))/(2^2+1^2)\\\\=(-3-6i)/(5)`