Question

Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two , solve for f(g(x)) when x = 1. (1 point)?

Answer 1

we have that
f(x) = x² + 3x + 6
and
g(x) = (x - 3)/2

step 1
solve for f(g(x)) when x = 1.

We want to evaluate f(g(1))

So g(x) = (x - 3)/2

when x =1

g(1) = (1 - 3) /2 = -2/2 = -1

So

f(g(1)) = f(-1) = (-1)² + 3(-1) + 6 = 1 - 3 + 6 = 4

the answer is

4