Question

Find the perimeter of the image below: Figure PQRST is shown. P is at negative 2, 11. Q is at negative 4, 5. R is at 2, 0. S is at 1, 7. T is at 8, 7. 37 units 38 units 39 units 40 units

Answer 1

For this case, the first thing to do is to graph the ordered pairs and join the points.
Then, we use the formula of distance between points:

`d = √((x2-x1)^2 + (y2-y1)^2)`
We have then:

For TP:

`TP = √((-2-8)^2 + (11-7)^2)`

`TP = 10.77032961`

For PQ:

`PQ = √((-4-(-2))^2 + (5-11)^2)`

`PQ = 6.32455532`

For QR:

`QR = √((2-(-4))^2 + (0-5)^2)`

`QR =  7.81024968`

For RS:

`RS = √((1-2)^2 + (7-0)^2)`

`RS =  7.07106781`

For ST:

`ST = √((8-1)^2 + (7-7)^2)`

`ST =  7`

Then, the perimeter of the figure is the sum of the lengths:

`P = 10.7703296 + 6.32455532 + 7.81024968 + 7.07106781 + 7 P = 38.97`
Rounding off we have:

`P = 39`

Answer:
the perimeter of the image is:
39 units