Question

The pythagorean theroy if a 4=a 8=b what is c

Answer 1

If a = 4 and b = 8 are the legs and c is a hypotenuse then:


`a^2+b^2=c^2`

Substitute:


`c^2=4^2+8^2\\\\c^2=16+64\\\\c^2=80\to c=√(80)\\\\c=√(16\cdot5)\to c=4\sqrt5`

If a = 4 and c are the legs and b = 8 is hypotenuse, then:


`a^2+c^2=b^2`

Substitute:


`4^2+c^2=8^2\\\\16+c^2=64\ \ \ |-16\\\\c^2=48\to c=√(48)\\\\c=√(16\cdot3)\to c=4\sqrt3`

Answer 2

a^2+b^2=c^2
4^2+8^2=c^2
16+64=c^2
c^2=80
c=the square root of 80 or about 8.9442719......