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The perimeter of triangle RXA is 24. If RX = 4 and RA = 11, find XP and PA. A. XP = 1.5, PA = 7.5 B. XP = 2.4, PA = 6.6 C. XP = 3, PA = 6 D. XP = 4, PA = 5
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The perimeter of triangle RXA is 24. If RX = 4 and RA = 11, find XP and PA. A. XP = 1.5, PA = 7.5 B. XP = 2.4, PA = 6.6 C. XP = 3, PA = 6 D. XP = 4, PA = 5

User Konyak
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the picture in the attached figure

we know that
RX+RA+XA=24
XA=24-RA-RX------> XA=24-11-4----> XA=9
XA=XP+PA
so
XP+PA=9------> XP=9-PA-----> equation 1

RX/XP=RA/PA

11*XP=4*PA-----> equation 2
substitute equation 1 in equation 2
11*[9-PA]=4*PA-----> 99-11*PA=4*PA----> 15*PA=99----> PA=99/15
PA=6.6
XP=9-PA-----> XP=9-6.6----> XP=2.4

the answer is the option
B. XP = 2.4, PA = 6.6

The perimeter of triangle RXA is 24. If RX = 4 and RA = 11, find XP and PA. A. XP-example-1
User Matan Shushan
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