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(1)/(4p)(x-h)^(2)+k=0 Multiply the equation by 4p. Explain how different values of k affect the number of zeros of the polynomial. Consider k > 0, k = 0, and k < 0. Assume p > 0.
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Dec 19, 2019
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(1)/(4p)(x-h)^(2)+k=0
Multiply the equation by 4p. Explain how different values of k affect the number of zeros of the polynomial. Consider k > 0, k = 0, and k < 0. Assume p > 0.
Mathematics
high-school
Alireza Afzal Aghaei
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Alireza Afzal Aghaei
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Assume that
and
multiply the equation
by 4p. Then you obtain the equation
.
1) If k>0, then 4pk>0 and the equation doesn't have solutions, because
and this is unreal.
2) If k=0, then 4pk=0 and
. There is one solution x=h.
2) If k<0, then 4pk<0 and the equation
has two different solutions
and
.
Hoang Dao
answered
Dec 23, 2019
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Hoang Dao
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