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Factor -7x^3+21x^2+3x-9 by grouping

User Krevedko
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I note immediately that -7x^2 is a factor of the 1st 2 terms:  -7x^2(x-3), and that 3x-9 divided by (x-3) is 3.  Thus, the factors are (x-3) and (3-7x^2).
User Jazzzzzz
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4 votes

Answer: The factorised form is


(x-3)(-7x^2+3)

Explanation:

Since we have given that


-7x^3+21x^2+3x-9

We need to factorise the above expression by grouping:


(-7x^3+21x^2)+(3x-9)\\\\=-7x^2(x-3)+3(x-3)\\\\=(x-3)(-7x^2+3)

Hence, the factorised form is


(x-3)(-7x^2+3)

User Darren Bishop
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