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If f(x) = sqrt x-3, which inequality can be used to find the domain of f(x)?

sqrt x-3 >/= 0
x - 3 >/= 0
sqrt x - 3 = 0
x - 3 = 0

User Chiina
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If your function is this:
y= √(x-3), then you find the domain by setting the radicand, the "x-3", greater than or equal to 0.
x-3 \geq 0 so
x \geq 3. Therefore, the domain is all values of x that are greater than or equal to 3.
User Kurczak
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