Question

Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After 2 hours, they are 232 miles apart. What is the speed of each car? 52 mph; 64 mph 55 mph; 70 mph 92 mph; 104 mph 98 mph; 110 mph?

Answer 1

d = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64

Answer 2

The first cars speed is X miles per hour.
The 2nd cars speed is X + 12 miles per hour

X + X +12 = 232 / 2

2x +12 = 116

2x = 116-12

2x = 104

x = 104 / 2
x = 52

x+12 = 52+12 = 64


The 2 cars are driving 52 and 64 miles per hour