Question

The point-slope form of the equation of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). What is the standard form of the equation for this line?

Answer 1

Explanation:

A) x-4y=8

Answer 2

Multiply by 4 and rearrange.

... 4y -4 = x - 12

... -4 = x - 4y - 12 . . . . . . subtract 4y

... x - 4y = 8 . . . . . . . . . . add 12. This is standard form.