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If a 4.0Ω resistor, a 6.0Ω resistor, and an 8.0Ω resistor are connected in parallel across a 12 volt battery, what is the total current of the circuit?
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If a 4.0Ω resistor, a 6.0Ω resistor, and an 8.0Ω resistor are connected in parallel across a 12 volt battery, what is the total current of the circuit?

User Aduguid
by
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1 Answer

4 votes
1/R=1/4+1/6+1/8
1/R=6/24+4/24+3/24
1/R=13/24
R=24/13=1.846153recurring ( hold full answer in calculator)

I=V/R =12/1.846153

or use the fraction I =12x 13/24=13/2
User Izidor
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